\(\left\{ \begin{array}{l}9{x^2}-14x = y,\\9x-14 = y\end{array} \right.\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\left\{ \begin{array}{l}9{x^2}-14x = 9x-14,\\y = 9x-14\end{array} \right.\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\left\{ \begin{array}{l}9{x^2}-23x + 14 = 0,\\y = 9x-14.\end{array} \right.\)
\(9{x^2}-23x + 14 = 0;\,\,\,\,\,\,\,\,D = {\left( {-23} \right)^2}-4 \cdot 9 \cdot 14 = 25;\,\,\,\,\,\,\,\,\,\left[ \begin{array}{l}x = \dfrac{{23 + 5}}{{2 \cdot 9}} = \dfrac{{14}}{9},\\x = \dfrac{{23-5}}{{2 \cdot 9}} = 1.\end{array} \right.\)
Если \(x = \dfrac{{14}}{9},\) то \(y = 9 \cdot \dfrac{{14}}{9}-14 = 0.\)
Если \(x = 1,\) то \(y = 9 \cdot 1-14 = -5.\)
Ответ: \(\left( {1;\,-5} \right),\,\,\;\left( {\dfrac{{14}}{9};\,0} \right).\)