\(\left\{ \begin{array}{l}4{x^2}-3x = y,\\8x-6 = y\end{array} \right.\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\left\{ \begin{array}{l}4{x^2}-3x = 8x-6,\\y = 8x-6\end{array} \right.\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\left\{ \begin{array}{l}4{x^2}-11x + 6 = 0,\\y = 8x-6.\end{array} \right.\)
\(4{x^2}-11x + 6 = 0;\,\,\,\,\,\,\,\,D = {\left( {-11} \right)^2}-4 \cdot 4 \cdot 6 = 25;\,\,\,\,\,\,\,\,\,\left[ \begin{array}{l}x = \dfrac{{11 + 5}}{{2 \cdot 4}} = 2,\\x = \dfrac{{11-5}}{{2 \cdot 4}} = \dfrac{3}{4}.\end{array} \right.\)
Если \(x = 2,\) то \(y = 8 \cdot 2-6 = 10.\)
Если \(x = \dfrac{3}{4},\) то \(y = 8 \cdot \dfrac{3}{4}-6 = 0.\)
Ответ: \(\left( {2;\,10} \right),\,\,\;\left( {\dfrac{3}{4};\,0} \right).\)