\(\left\{ \begin{array}{l}5{x^2}-11x = y,\\5x-11 = y\end{array} \right.\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\left\{ \begin{array}{l}5{x^2}-11x = 5x-11,\\y = 5x-11\end{array} \right.\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\left\{ \begin{array}{l}5{x^2}-16x + 11 = 0,\\y = 5x-11.\end{array} \right.\)
\(5{x^2}-16x + 11 = 0;\,\,\,\,\,\,\,\,D = {\left( {-16} \right)^2}-4 \cdot 5 \cdot 11 = 36;\,\,\,\,\,\,\,\,\,\left[ \begin{array}{l}x = \dfrac{{16 + 6}}{{2 \cdot 5}} = \dfrac{{11}}{5},\\x = \dfrac{{16-6}}{{2 \cdot 5}} = 1.\end{array} \right.\)
Если \(x = \dfrac{{11}}{5},\) то \(y = 5 \cdot \dfrac{{11}}{5}-11 = 0.\)
Если \(x = 1,\) то \(y = 5 \cdot 1-11 = -6.\)
Ответ: \(\left( {1;\,-6} \right),\,\,\;\left( {\dfrac{{11}}{5};\,0} \right).\)