\(\left( {x-2} \right)\left( {x-3} \right)\left( {x-4} \right) = \left( {x-2} \right)\left( {x-3} \right)\left( {x-5} \right)\,\,\,\,\,\,\, \Leftrightarrow \)
\( \Leftrightarrow \,\,\,\,\,\,\,\left( {x-2} \right)\left( {x-3} \right)\left( {x-4} \right)-\left( {x-2} \right)\left( {x-3} \right)\left( {x-5} \right) = 0\,\,\,\,\,\,\, \Leftrightarrow \)
\( \Leftrightarrow \,\,\,\,\,\,\,\left( {x-2} \right)\left( {x-3} \right)\left( {\left( {x-4} \right)-\left( {x-5} \right)} \right) = 0\,\,\,\,\,\,\, \Leftrightarrow \)
\( \Leftrightarrow \,\,\,\,\,\,\,\left( {x-2} \right)\left( {x-3} \right)\left( {x-4-x + 5} \right) = 0\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\,\,\left( {x-2} \right)\left( {x-3} \right) = 0\,\,\,\,\,\,\, \Leftrightarrow \)
\( \Leftrightarrow \,\,\,\,\,\,\,\left[ {\begin{array}{*{20}{c}}{x-2 = 0,}\\{x-3 = 0\,}\end{array}} \right.\,\,\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\,\,\,\,\left[ {\begin{array}{*{20}{c}}{x = 2,}\\{x = 3.}\end{array}} \right.\)
Ответ: 2; 3.