Пусть \(\angle \,CAD = \angle \,BAD = \alpha ;\,\,\,\,\,\,\,\,\,\,\,\angle \,CBE = \angle \,ABE = \beta .\)
Из треугольника АВС:
\(2\alpha + 2\beta + {58^ \circ } = {180^ \circ }\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\,\,\,\,2\alpha + 2\beta = {122^ \circ }\,\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\,\,\,\,\alpha + \beta = {61^ \circ }.\)
Из треугольника АOВ:
\(\angle \,AOB + \alpha + \beta = {180^ \circ }\,\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\,\,\,\,\,\angle \,AOB + {61^ \circ } = {180^ \circ }\,\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\,\,\,\alpha + \rho = {119^ \circ }.\)
Ответ: 119.